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parseTree(Idc : LDAPConnection, base : String, rootDN : String) : DefaultMutableTreeNode parseTree(Idc : LDAPConnection, base : String) : DefaultMutableTreeNode printTree(root : DefaultMutableTreeNode) : void normalizeDN(dn : String) : String createEntryNode(entry : LDAPEntry) : DefaultMutableTreeNode getRootLevelManagers(Idc : LDAPConnection, base : String, root : DefaultMutableTreeNode) : Hashtable getSubordinates(Idc : LDAPConnection, base : String, managerTable : Hashtable) : Hashtable getValueFromEntry(entry : LDAPEntry, name : String) : String getValueFromNode(node : DefaultMutableTreeNode, name : String) : String getDNFromNode(node : DefaultMutableTreeNode) : String getManagerFromEntry(entry : LDAPEntry) : String getTitleFromEntry(entry : LDAPEntry) : String addEntriesToTree(root : DefaultMutableTreeNode, managers : Hashtable, managerTable : Hashtable) : DefaultMutableTreeNode printManagers(managers : Hashtable) : void main(args : String[]) : void

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Although the rst list has numbers of different types (int and float), these types can be compared with each other so that sorting a list containing them works ne But the second list has a string and this cannot be sensibly compared with a number, and so a TypeError exception is raised If we want to sort a list that has integers, oating-point numbers, and strings that contain numbers, we can give float() as the key function:

void move(int dx, int dy) { move((float)dx, (float)dy); } void move(float dx, float dy) { x += dx; y += dy; } float getX() { return x; } float getY() { return y; } }

sorted(["13", -75, "5", 4, "-24", 1], key=float)

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The method parseTree starts by creating an empty root node and then creating a Hashtable of all entries that do not have a manager attribute It prints a message indicating the number found:

class Point {

This returns the list [-75, '-24', 1, '13', 4, '5'] Notice that the list s values are not changed, so strings remain strings If any of the strings cannot be converted to a number (eg, spanner ), a ValueError exception will be raised

/** * Read person entries in a directory subtree, and * sort the results by reporting relationships * * @param ldc connected and authenticated LDAPConnection * object * @param base base DN from which to search for entries * @param rootDN DN of the top manager node to return * @return the root node of a tree, or null * on failure * @throws LDAPException on failure in searching */ static public DefaultMutableTreeNode parseTree( LDAPConnection ldc, String base, String rootDN ) throws LDAPException {

This example corrects the errors of the example in the preceding section:

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Since Python uses object references, when we use the assignment operator (=), no copying takes place If the right-hand operand is a literal such as a string or a number, the left-hand operand is set to be an object reference that refers to the in-memory object that holds the literal s value If the right-hand operand is an object reference, the left-hand operand is set to be an object reference that refers to the same object as the right-hand operand One consequence of this is that assignment is very ef cient

class RealPoint extends Point { float x = 00f, y = 00f;

// Get root-level managers and add them to the root; // keep references in a Hashtable We consider a root// level manager to be anyone who doesn t have a // manager In reality, some of the entries without managers may be // highly placed individual contributors, and some // may just not have their directory info up-to-date DefaultMutableTreeNode root = new DefaultMutableTreeNode(); Hashtable rootEntries = getRootLevelManagers( ldc, base, root ); Systemoutprintln( rootEntriessize() + " entries " + "do not have a manager" );

When we assign large collections, such as long lists, the savings are very apparent Here is an example:

Here the overriding methods getX and getY in class RealPoint have the same return types as the methods of class Point that they override, so this code can be successfully compiled

>>> songs = ["Because", "Boys", "Carol"] >>> beatles = songs >>> beatles, songs (['Because', 'Boys', 'Carol'], ['Because', 'Boys', 'Carol'])

The getRootLevelManagers method searches for all entries that match rootFilter, which in this case is declared as follows:

int x = 0, y = 0; int getX() { return x; } int getY() { return y; } int color;

Here, a new object reference (beatles) has been created, and both object references refer to the same list no copying has taken place Since lists are mutable, we can apply a change For example:

void move(int dx, int dy) { x += dx; y += dy; }

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