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At this point, we have developed a fairly solid understanding of the .crx file format. This section provides a brief overview of all the information gathered in this reversing session. You have deciphered the meaning of most of the .crx fields, at least the ones that matter if you were to write a program that views or dumps an archive. Figure 6.2 illustrates what you know about the Cryptex header. The Cryptex header comprises a standard 8-byte signature that contains the string CrYpTeX9. The header contains a 16-byte MD5 checksum that is used for confirming the user-supplied password. Cryptex archives are encrypted using a Crypto-API implementation of the triple-DES algorithm. The tripleDES key is generated by hashing the user-supplied password using the SHA

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These relations can be elaborated for more variables. The moments of multivariate distributions are found by extension from the de nitions for single variables. Let Z be some function g of X and Y , i.e. Z = g(X, Y ). Then the expected value or mean of Z is E[Z] Z = E[g(X, Y )] =

call sub neg sbb and add ret SomeFunc eax, 4 eax eax, eax al, -52 eax, 54

g(xi , yi )pX,Y (xi , yi )

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You ll notice that this sequence also uses the NEG/SBB combination, except that this one has somewhat more complex functionality The sequence starts by calling a function and subtracting 4 from its return value It then invokes NEG and SBB in order to perform a zero test on the result, just as you saw in the previous example If after the subtraction the return value from SomeFunc is zero, SBB will set EAX to zero If the subtracted return value is nonzero, SBB will set EAX to 1 (or 0xffffffff in hexadecimal) The next two instructions are the clever part of this sequence Let s start by looking at that AND instruction Because SBB is going to set EAX either to zero or to 0xffffffff, we can consider the following AND instruction to be similar to a conditional assignment instruction (much like the CMOV instruction discussed later).

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By ANDing EAX with a constant, the code is essentially saying: if the result from SBB is zero, do nothing If the result is 1, set EAX to the specified constant After doing this, the code unconditionally adds 54 to EAX and returns to the caller The challenge at this point is to try and figure out what this all means This sequence is obviously performing some kind of transformation on the return value of SomeFunc and returning that transformed value to the caller Let s try and analyze the bottom line of this sequence It looks like the return value is going to be one of two values: If the outcome of SBB is zero (which means that SomeFunc s return value was 4), EAX will be set to 54.

(A.31)

If SBB produces 0xffffffff, EAX will be set to 2, because the AND instruction will set it to 52, and the ADD instruction will bring the value up to 2 This is a sequence that compares a pair of integers, and produces (without the use of any branches) one value if the two integers are equal and another value if they are unequal The following is a C version of the assembly language snippet from earlier:.

if (SomeFunc() == 4) return 54; else return 2;

or E[Z] Z = E[g(X, Y )] =

Using arithmetic sequences to implement branchless logic is a very limited technique. For more elaborate branchless logic, compilers employ conditional instructions (provided that such instructions are available on the target CPU architecture). The idea behind conditional instructions is that instead of having to branch to two different code sections, compilers can sometimes use special instructions that are only executed if certain conditions exist. If the conditions aren t met, the processor will simply ignore the instruction and move on. The IA-32 instruction set does not provide a generic conditional execution prefix that applies to all instructions. To conditionally perform operations, specific instructions are available that operate conditionally.

java data matrix reader

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